diff --git a/02_activities/assignments/DC_Cohort/Assignment1.md b/02_activities/assignments/DC_Cohort/Assignment1.md
index d5ff55ce4..82243b7be 100644
--- a/02_activities/assignments/DC_Cohort/Assignment1.md
+++ b/02_activities/assignments/DC_Cohort/Assignment1.md
@@ -206,8 +206,20 @@ Link if you encounter a paywall: https://archive.is/srKHV or https://web.archive
 **What values systems are embedded in databases and data systems you encounter in your day-to-day life?**
 
 Consider, for example, concepts of fariness, inequality, social structures, marginalization, intersection of technology and society, etc.
-
-
 ```
 Your thoughts...
 ```
+China's national ID (身份证 shenfenzheng) and household registration (户口 hukou). Similar to what I have read about the database of Pakistan, I think these systems reflect certain heteronormative assumptions about gender and family structures.
+
+First, the official gender classification recorded on Chinese national IDs is binary — either male or female. This excludes people who identify as non-binary, as there is no option that accurately represents their gender identity.
+Consequently, non-binary individuals may feel marginalized or invisible within the legal system, since their identities cannot be adequately represented in official records. 
+What I find particularly interesting is that this binary classification is treated as a seemingly natural and objective way of categorizing people, even though it reflects particular social understandings of gender.
+
+Meanwhile, because same-sex marriage is not legally recognized in mainland China, same-sex couples cannot register as married partners. This can create significant difficulties when dealing with legal and administrative matters.
+For instance, if one partner experiences a medical emergency and cannot make decisions independently, the other partner is not automatically recognized as their legal spouse or next of kin.
+Same-sex couples do not automatically receive the same legal recognition as married heterosexual couples.
+
+Furthermore, even if same-sex partners raise children together, both partners may not be legally recognized as the children's parents in the household registration system.
+In particular, a non-biological parent may face difficulties establishing a legally recognized parental relationship, despite having actively participated in raising the child.
+This can create complications in matters involving guardianship, inheritance, and other parental responsibilities involved in schooling and children's education. 
+
diff --git a/02_activities/assignments/DC_Cohort/assignment1.sql b/02_activities/assignments/DC_Cohort/assignment1.sql
index a80923591..058a96d24 100644
--- a/02_activities/assignments/DC_Cohort/assignment1.sql
+++ b/02_activities/assignments/DC_Cohort/assignment1.sql
@@ -6,7 +6,7 @@
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
 --QUERY 1
-
+SELECT * FROM customer ;
 
 
 
@@ -17,9 +17,10 @@
 sorted by customer_last_name, then customer_first_ name. */
 --QUERY 2
 
-
-
-
+SELECT * 
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
 --END QUERY
 
 
@@ -27,9 +28,10 @@ sorted by customer_last_name, then customer_first_ name. */
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. 
 Limit to 25 rows of output. */
 --QUERY 3
-
-
-
+SELECT *
+FROM customer_purchases
+WHERE product_id = 4 OR product_id = 9
+LIMIT 25;
 
 --END QUERY
 
@@ -42,10 +44,10 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 Limit to 25 rows of output.
 */
 --QUERY 4
-
-
-
-
+SELECT *, quantity * cost_per_quantity AS price
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 AND 10
+LIMIT 25;
 --END QUERY
 
 
@@ -55,9 +57,12 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 --QUERY 5
-
-
-
+SELECT product_id, product_name,
+				CASE
+							WHEN product_qty_type = 'unit' THEN 'unit'
+							ELSE 'bulk'
+				END AS prod_qty_type_condensed
+FROM product;
 
 --END QUERY
 
@@ -67,8 +72,16 @@ add a column to the previous query called pepper_flag that outputs a 1 if the pr
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 --QUERY 6
 
-
-
+SELECT product_id, product_name,
+				CASE
+							WHEN product_qty_type = 'unit' THEN 'unit'
+							ELSE 'bulk'
+				END AS prod_qty_type_condensed,
+				CASE
+							WHEN product_name LIKE  '%pepper%' THEN 1
+							ELSE 0
+				END AS pepper_flag
+FROM product;
 
 --END QUERY
 
@@ -78,9 +91,12 @@ contains the word “pepper” (regardless of capitalization), and otherwise out
 vendor_id field they both have in common, and sorts the result by market_date, then vendor_name.
 Limit to 24 rows of output. */
 --QUERY 7
-
-
-
+SELECT *
+FROM vendor AS v
+INNER JOIN vendor_booth_assignments AS vba
+ON v.vendor_id = vba.vendor_id
+ORDER BY market_date, vendor_name
+LIMIT 24;
 
 --END QUERY
 
@@ -92,9 +108,10 @@ Limit to 24 rows of output. */
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 --QUERY 8
-
-
-
+SELECT vendor_id,
+				SUM (booth_number) AS vendor_renting_times
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 --END QUERY
 
@@ -106,8 +123,13 @@ of customers for them to give stickers to, sorted by last name, then first name.
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 --QUERY 9
 
-
-
+SELECT cp.customer_id, cp.quantity, cp.cost_per_quantity, c.customer_id, c.customer_first_name, c.customer_last_name,
+				SUM(cp.quantity * cp.cost_per_quantity) AS total_purchase
+FROM customer_purchases AS cp
+INNER JOIN customer AS c
+ON cp.customer_id = c.customer_id
+GROUP BY c.customer_id
+HAVING total_purchase > 2000;
 
 --END QUERY
 
@@ -124,9 +146,12 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 --QUERY 10
+CREATE TEMP TABLE new_vendor AS
+SELECT * 
+FROM vendor;
 
-
-
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal' )
 
 --END QUERY
 
@@ -134,14 +159,14 @@ VALUES(col1,col2,col3,col4,col5)
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
 
-HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
+HINT: you might need to search for strfrtime modifiers sqlite on the web to know what the modifiers for month 
 and year are! 
 Limit to 25 rows of output. */
 --QUERY 11
-
-
-
-
+SELECT customer_id, 
+				STRFTIME('%m', market_date) AS month,
+				STRFTIME('%Y', market_date) AS year
+FROM customer_purchases;
 --END QUERY
 
 
@@ -152,8 +177,13 @@ HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement...
 AND be sure you remove the LIMIT from the previous query before aggregating!! */
 --QUERY 12
-
-
-
-
---END QUERY
+SELECT customer_id, 
+				quantity,
+				cost_per_quantity,
+				STRFTIME('%m', market_date) AS month,
+				STRFTIME('%Y', market_date) AS year,
+				SUM(quantity * cost_per_quantity) AS total_purchase
+FROM customer_purchases
+WHERE month = '04' AND year = '2022'
+GROUP BY customer_id, year, month;
+--END QUERY
\ No newline at end of file
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